![]() To go back to radian, press MODE, ↓, ↓, ENTER. Program automatically switches your calculator into degree mode. If you prefer your calculator in radian mode, make sure you switch it back once you're done running this program! This I made these programs because I didn't want to have to plug every single equation into my calculator for physics class. The code for PROJMOT.8xp and PMXY.8xp is essentially the same, just with a few tweaks to the solution screen! Prompts Vx and Vy to calculate your answers. ![]() PMXY.8xp: Same exact program as PROJMOT.8xp, just skipping velocity & angle. Gives you the most exact possible values as it doesn't round to a certain amount of digits. Velocity and angle! As far as I can tell, it is the simplest program out there that will tell you all of these values. PROJMOT.8xp: This is a very simple physics program for projectile motion problems that gives you Vx, Vy, Tup, Ttotal, and Dh from just ![]() TI-84 Plus C Silver Edition BASIC Science Programs.TI-84 Plus C Silver Edition BASIC Math Programs.TI-84 Plus C Silver Edition BASIC Programs.TI-83 Plus/TI-84 Plus BASIC Science Programs.TI-83 Plus/TI-84 Plus BASIC Math Programs.This program should run on any TI-83 or 84 series calculator, including the CE and CSE. Currently, isentropic flow, the Prantdl-Meyer function (and several other formulae that may assist with that), and normal shocks are supported. Up to TI-83/84 Plus Flash Applications: basicbuilder: folder : TI-83/84 Plus Flash Science Programs (BasicBuilder) chemicalequationbalancer.zip: 60k: 12-06-03: Chemical Equation Balancer This application can balance chemical equations, calculate molar masses and do some other stuff. Remember that if there's no coefficient in front of an element, it's assumed that the coefficient is 1.FLOW84 is meant to bring a subset of compressible flow calculations to your TI-83/84. Now the number of atoms in each element is the same on both sides of the equation, so the equation is balanced. To balance this, add the coefficient 2 before H2 on the left side of the equation so there are 4 hydrogen atoms on each side, like 2H2 + O2 → 2H2O. However, subscripts can't be changed and are always multiplied by the coefficient, which means there are now 4 hydrogen atoms on the right side of the equation and only 2 hydrogen atoms on the left side. For the equation H2 + O2 → H2O, you would add the coefficient 2 before H2O on the right side so that there are 2 oxygen atoms on each side of the equation, like H2 + O2 → 2H2O. To balance the equation, you'll need to add coefficients to change the number of atoms on one side to match the other. Since the number of atoms in each element isn't identical on both sides, the equation is not balanced. There are 2 hydrogen atoms and 1 oxygen atom on the right, so you would write "H=2" and "O=1" under the right side. For the equation H2 + O2 → H2O, there are 2 hydrogen atoms being added to 2 oxygen atoms on the left, so you would write "H=2" and "O=2" under the left side. For example, your equation should look something like "H2 + O2 → H2O." Count the number of atoms in each element on each side of the equation and list them under that side. To balance a chemical equation, first write out your given formula with the reactants on the left of the arrow and the products on the right. If the value you assigned returns coefficients that have a greatest common factor (GCF), simplify the chemical equation by dividing each value by the GCF.If there is only one fraction, multiply all values by that values denominator. If the value you assigned returns fractional values, just multiply all values by the least common multiple (LCM) of the denominators to get rid of the fractions.This shows us the values are as follows:. ![]() Since H: 2b = 3c + d, we can calculate b like this:.Then start solving the system of equations to get the following values: To quickly do this, take one variable and assign a value to it.You must find the one where every variable is in its smallest, non-fractional form. Since there are more variables than equations, there are multiple solutions. Solve this system of equations to get the numeric value for all the coefficients.
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